Solve the following inequality.-2/3x>8A) x < - 4B) x > - 4C) x > -12D) x < -12

First simplify.
[tex]-\frac{2}{3}x \ \textgreater \ \mathrm{Multiply\:fractions}:\ \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ -\frac{2x}{3} [/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)} \ \textgreater \ \ \textgreater \ \frac{2x}{3}\ \textless \ -8[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:}3 \ \textgreater \ \frac{3\cdot \:2x}{3}\ \textless \ 3\left(-8\right) \ \textgreater \ Simplify \ \textgreater \ 2x\ \textless \ -24 [/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}2 \ \textgreater \ \frac{2x}{2}\ \textless \ \frac{-24}{2} \ \textgreater \ Simplify \ \textgreater \ x\ \textless \ -12[/tex]

[tex]Therefore\; x\ \textless \ -12 \;is\;our\;answer![/tex]

Hope this helps!