The work of a student to solve a set of equations is shown:Equation A: y = 15 − 2zEquation B: 2y = 3 − 4zStep 1: −2(y) = −2(15 − 2z) [Equation A is multiplied by −2.]2y = 3 − 4z [Equation B]Step 2: −2y = 15 − 2z [Equation A in Step 1 is simplified.]2y = 3 − 4z [Equation B]Step 3: 0 = 18 − 6z [Equations in Step 2 are added.]Step 4: 6z = 18 Step 5: z = 3 In which step did the student first make an error?a: Step1b: Step 2c: Step 3d: Step 4

Answer:Option B. Step 2Step-by-step explanation:we have[tex]y=15-2z[/tex] ----> equation A[tex]2y=3-4z[/tex] ----> equation Bstep 1Multiply equation A by -2 both sides[tex]-2(y)=-2(15-2z)[/tex] step 2Simplify equation A[tex]-2(y)=-2(15-2z)[/tex] [tex]-2y=-30+4z[/tex] -----> equation AThe first error is in step 2The student's mistake was to multiply equation A by -2 on the left side only and not on both sides.step 3Adds equation A and equation B[tex]-2y=-30+4z\\2y=3-4z\\---------\\0=-30+4z+3-4z\\27=0[/tex]The system has no solutionThe lines are parallel